Base | Representation |
---|---|
bin | 10100101101110110… |
… | …11110111110000101 |
3 | 1001201010012202010122 |
4 | 22112323132332011 |
5 | 140234230012331 |
6 | 5035345231325 |
7 | 542421243446 |
oct | 122673367605 |
9 | 31633182118 |
10 | 11122110341 |
11 | 4798161131 |
12 | 21a4932545 |
13 | 108330cca4 |
14 | 7771b92cd |
15 | 45166017b |
hex | 296edef85 |
11122110341 has 2 divisors, whose sum is σ = 11122110342. Its totient is φ = 11122110340.
The previous prime is 11122110331. The next prime is 11122110449. The reversal of 11122110341 is 14301122111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10952459716 + 169650625 = 104654^2 + 13025^2 .
It is an emirp because it is prime and its reverse (14301122111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11122110341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11122110301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561055170 + 5561055171.
It is an arithmetic number, because the mean of its divisors is an integer number (5561055171).
Almost surely, 211122110341 is an apocalyptic number.
It is an amenable number.
11122110341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122110341 is an equidigital number, since it uses as much as digits as its factorization.
11122110341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11122110341 its reverse (14301122111), we get a palindrome (25423232452).
The spelling of 11122110341 in words is "eleven billion, one hundred twenty-two million, one hundred ten thousand, three hundred forty-one".
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