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11122111131151 is a prime number
BaseRepresentation
bin1010000111011001000101…
…1110111010111000001111
31110101021010001021212022111
42201312101132322320033
52424211040422144101
635353232144524451
72225355165523126
oct241662136727017
943337101255274
1011122111131151
1135a8951865119
1212b7658620727
13628a6cac5947
142a6455024abd
151444a1b75251
hexa1d917bae0f

11122111131151 has 2 divisors, whose sum is σ = 11122111131152. Its totient is φ = 11122111131150.

The previous prime is 11122111131149. The next prime is 11122111131211. The reversal of 11122111131151 is 15113111122111.

It is a m-pointer prime, because the next prime (11122111131211) can be obtained adding 11122111131151 to its product of digits (60).

It is a weak prime.

It is an emirp because it is prime and its reverse (15113111122111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11122111131151 - 21 = 11122111131149 is a prime.

Together with 11122111131149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11122111131251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561055565575 + 5561055565576.

It is an arithmetic number, because the mean of its divisors is an integer number (5561055565576).

Almost surely, 211122111131151 is an apocalyptic number.

11122111131151 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122111131151 is an equidigital number, since it uses as much as digits as its factorization.

11122111131151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60, while the sum is 22.

Adding to 11122111131151 its reverse (15113111122111), we get a palindrome (26235222253262).

The spelling of 11122111131151 in words is "eleven trillion, one hundred twenty-two billion, one hundred eleven million, one hundred thirty-one thousand, one hundred fifty-one".