Base | Representation |
---|---|
bin | 110011110010101001… |
… | …0111010100001000101 |
3 | 101122002012011110102002 |
4 | 1213211102322201011 |
5 | 3310240101420031 |
6 | 123032210355045 |
7 | 11015106643142 |
oct | 1474522724105 |
9 | 348065143362 |
10 | 111221123141 |
11 | 43194473a97 |
12 | 1967b88ba85 |
13 | a6464a8a8b |
14 | 55514513c9 |
15 | 2d5e406ccb |
hex | 19e54ba845 |
111221123141 has 2 divisors, whose sum is σ = 111221123142. Its totient is φ = 111221123140.
The previous prime is 111221123081. The next prime is 111221123179. The reversal of 111221123141 is 141321122111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56796899041 + 54424224100 = 238321^2 + 233290^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111221123141 is a prime.
It is a super-3 number, since 3×1112211231413 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111221123191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55610561570 + 55610561571.
It is an arithmetic number, because the mean of its divisors is an integer number (55610561571).
Almost surely, 2111221123141 is an apocalyptic number.
It is an amenable number.
111221123141 is a deficient number, since it is larger than the sum of its proper divisors (1).
111221123141 is an equidigital number, since it uses as much as digits as its factorization.
111221123141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96, while the sum is 20.
Adding to 111221123141 its reverse (141321122111), we get a palindrome (252542245252).
The spelling of 111221123141 in words is "one hundred eleven billion, two hundred twenty-one million, one hundred twenty-three thousand, one hundred forty-one".
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