Base | Representation |
---|---|
bin | 10100101101110111… |
… | …10101011000011101 |
3 | 1001201010101102001122 |
4 | 22112323311120131 |
5 | 140234240432031 |
6 | 5035351220325 |
7 | 542422105211 |
oct | 122673653035 |
9 | 31633342048 |
10 | 11122202141 |
11 | 47982140a6 |
12 | 21a49776a5 |
13 | 10833429cb |
14 | 777200941 |
15 | 45167c47b |
hex | 296ef561d |
11122202141 has 2 divisors, whose sum is σ = 11122202142. Its totient is φ = 11122202140.
The previous prime is 11122202131. The next prime is 11122202191. The reversal of 11122202141 is 14120222111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7646628025 + 3475574116 = 87445^2 + 58954^2 .
It is a cyclic number.
It is not a de Polignac number, because 11122202141 - 210 = 11122201117 is a prime.
It is a super-3 number, since 3×111222021413 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11122202131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561101070 + 5561101071.
It is an arithmetic number, because the mean of its divisors is an integer number (5561101071).
Almost surely, 211122202141 is an apocalyptic number.
It is an amenable number.
11122202141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122202141 is an equidigital number, since it uses as much as digits as its factorization.
11122202141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11122202141 its reverse (14120222111), we get a palindrome (25242424252).
The spelling of 11122202141 in words is "eleven billion, one hundred twenty-two million, two hundred two thousand, one hundred forty-one".
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