Base | Representation |
---|---|
bin | 1010000111011001111111… |
… | …1101111001101000100000 |
3 | 1110101021201222112122220211 |
4 | 2201312133331321220200 |
5 | 2424212040124233121 |
6 | 35353312225143504 |
7 | 2225364206151652 |
oct | 241663775715040 |
9 | 43337658478824 |
10 | 11122354133536 |
11 | 35a8a66a49438 |
12 | 12b7705a8ab94 |
13 | 628aab258239 |
14 | 2a64793dc6d2 |
15 | 1444b8175ce1 |
hex | a1d9ff79a20 |
11122354133536 has 24 divisors (see below), whose sum is σ = 21919779161280. Its totient is φ = 5555426092608.
The previous prime is 11122354133503. The next prime is 11122354133543. The reversal of 11122354133536 is 63533145322111.
It is a super-2 number, since 2×111223541335362 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179686516 + ... + 179748403.
It is an arithmetic number, because the mean of its divisors is an integer number (913324131720).
Almost surely, 211122354133536 is an apocalyptic number.
11122354133536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
11122354133536 is a deficient number, since it is larger than the sum of its proper divisors (10797425027744).
11122354133536 is an equidigital number, since it uses as much as digits as its factorization.
11122354133536 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 359435896 (or 359435888 counting only the distinct ones).
The product of its digits is 194400, while the sum is 40.
Adding to 11122354133536 its reverse (63533145322111), we get a palindrome (74655499455647).
The spelling of 11122354133536 in words is "eleven trillion, one hundred twenty-two billion, three hundred fifty-four million, one hundred thirty-three thousand, five hundred thirty-six".
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