11123213002333 has 4 divisors (see below), whose sum is σ = 11126317447168. Its totient is φ = 11120108557500.

The previous prime is 11123213002331. The next prime is 11123213002393. The reversal of 11123213002333 is 33320031232111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11123213002333 - 2¹ = 11123213002331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11123213002298 and 11123213002307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11123213002331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1552217043 + ... + 1552224208.

It is an arithmetic number, because the mean of its divisors is an integer number (2781579361792).

Almost surely, 2^{11123213002333} is an apocalyptic number.

It is an amenable number.

11123213002333 is a deficient number, since it is larger than the sum of its proper divisors (3104444835).

11123213002333 is an equidigital number, since it uses as much as digits as its factorization.

11123213002333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3104444834.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11123213002333 its reverse (33320031232111), we get a palindrome (44443244234444).

The spelling of 11123213002333 in words is "eleven trillion, one hundred twenty-three billion, two hundred thirteen million, two thousand, three hundred thirty-three".