Base | Representation |
---|---|
bin | 10000001011111100111… |
… | …101111110100100110010 |
3 | 10221100011021121200021122 |
4 | 100023330331332210302 |
5 | 121211040442333030 |
6 | 2211000552022242 |
7 | 143235651113252 |
oct | 20137475764462 |
9 | 3840137550248 |
10 | 1112345667890 |
11 | 39981a149006 |
12 | 15b6b6391982 |
13 | 80b8073a1c2 |
14 | 3bba2d85962 |
15 | 1de047518e5 |
hex | 102fcf7e932 |
1112345667890 has 32 divisors (see below), whose sum is σ = 2030843232000. Its totient is φ = 438596241408.
The previous prime is 1112345667871. The next prime is 1112345667907. The reversal of 1112345667890 is 987665432111.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 648335 + ... + 1626354.
It is an arithmetic number, because the mean of its divisors is an integer number (63463851000).
It is a 2-persistent number, because it is pandigital, and so is 2⋅1112345667890 = 2224691335780, but 3⋅1112345667890 = 3337037003670 is not.
Almost surely, 21112345667890 is an apocalyptic number.
1112345667890 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1112345667890 is a deficient number, since it is larger than the sum of its proper divisors (918497564110).
1112345667890 is a wasteful number, since it uses less digits than its factorization.
1112345667890 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2275394.
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 1112345667890 in words is "one trillion, one hundred twelve billion, three hundred forty-five million, six hundred sixty-seven thousand, eight hundred ninety".
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