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1112410201303 = 6611682920123
BaseRepresentation
bin10000001100000000110…
…100001001110011010111
310221100022210001022111001
4100030000310021303113
5121211204002420203
62211011215124131
7143240363461312
oct20140064116327
93840283038431
101112410201303
11399852615a05
1215b713b13647
1380b90c1375b
143bbab783979
151de0a24c91d
hex10300d09cd7

1112410201303 has 4 divisors (see below), whose sum is σ = 1114093122088. Its totient is φ = 1110727280520.

The previous prime is 1112410201237. The next prime is 1112410201337. The reversal of 1112410201303 is 3031020142111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1112410201303 - 229 = 1111873330391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112410201393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 841459401 + ... + 841460722.

It is an arithmetic number, because the mean of its divisors is an integer number (278523280522).

Almost surely, 21112410201303 is an apocalyptic number.

1112410201303 is a deficient number, since it is larger than the sum of its proper divisors (1682920785).

1112410201303 is an equidigital number, since it uses as much as digits as its factorization.

1112410201303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1682920784.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1112410201303 its reverse (3031020142111), we get a palindrome (4143430343414).

The spelling of 1112410201303 in words is "one trillion, one hundred twelve billion, four hundred ten million, two hundred one thousand, three hundred three".

Divisors: 1 661 1682920123 1112410201303