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11124134503 = 97114681799
BaseRepresentation
bin10100101110000110…
…01101001001100111
31001201021000120202121
422113003031021213
5140240234301003
65035500450411
7542444404006
oct122703151147
931637016677
1011124134503
114799313999
1221a5549a07
13108386b411
14777584c3d
1545190ecbd
hex2970cd267

11124134503 has 4 divisors (see below), whose sum is σ = 11238816400. Its totient is φ = 11009452608.

The previous prime is 11124134477. The next prime is 11124134509. The reversal of 11124134503 is 30543142111.

11124134503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11124134503 - 213 = 11124126311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11124134509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57340803 + ... + 57340996.

It is an arithmetic number, because the mean of its divisors is an integer number (2809704100).

Almost surely, 211124134503 is an apocalyptic number.

11124134503 is a deficient number, since it is larger than the sum of its proper divisors (114681897).

11124134503 is an equidigital number, since it uses as much as digits as its factorization.

11124134503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114681896.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11124134503 its reverse (30543142111), we get a palindrome (41667276614).

The spelling of 11124134503 in words is "eleven billion, one hundred twenty-four million, one hundred thirty-four thousand, five hundred three".

Divisors: 1 97 114681799 11124134503