1112414341303 has 4 divisors (see below), whose sum is σ = 1112416886128. Its totient is φ = 1112411796480.

The previous prime is 1112414341301. The next prime is 1112414341309. The reversal of 1112414341303 is 3031434142111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1112414341303 - 2¹ = 1112414341301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112414341301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431451 + ... + 1552732.

It is an arithmetic number, because the mean of its divisors is an integer number (278104221532).

Almost surely, 2^{1112414341303} is an apocalyptic number.

1112414341303 is a deficient number, since it is larger than the sum of its proper divisors (2544825).

1112414341303 is an equidigital number, since it uses as much as digits as its factorization.

1112414341303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2544824.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1112414341303 its reverse (3031434142111), we get a palindrome (4143848483414).

It can be divided in two parts, 111241 and 4341303, that added together give a palindrome (4452544).

The spelling of 1112414341303 in words is "one trillion, one hundred twelve billion, four hundred fourteen million, three hundred forty-one thousand, three hundred three".