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11124341213 is a prime number
BaseRepresentation
bin10100101110000111…
…11111100111011101
31001201021102002022112
422113003333213131
5140240312404323
65035505123405
7542446224446
oct122703774735
931637362275
1011124341213
114799445227
1221a5629565
13108391152b
147775da2cd
15451951178
hex2970ff9dd

11124341213 has 2 divisors, whose sum is σ = 11124341214. Its totient is φ = 11124341212.

The previous prime is 11124341177. The next prime is 11124341219. The reversal of 11124341213 is 31214342111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8160954244 + 2963386969 = 90338^2 + 54437^2 .

It is a cyclic number.

It is not a de Polignac number, because 11124341213 - 218 = 11124079069 is a prime.

It is a super-2 number, since 2×111243412132 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11124341219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562170606 + 5562170607.

It is an arithmetic number, because the mean of its divisors is an integer number (5562170607).

Almost surely, 211124341213 is an apocalyptic number.

It is an amenable number.

11124341213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11124341213 is an equidigital number, since it uses as much as digits as its factorization.

11124341213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

Adding to 11124341213 its reverse (31214342111), we get a palindrome (42338683324).

The spelling of 11124341213 in words is "eleven billion, one hundred twenty-four million, three hundred forty-one thousand, two hundred thirteen".