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111254601431 is a prime number
BaseRepresentation
bin110011110011101001…
…0100111111011010111
3101122011112011022222202
41213213102213323113
53310322134221211
6123035404115115
711015664336401
oct1474722477327
9348145138882
10111254601431
114320135a7a6
121968ab35a9b
13a6503cb00c
145555a87b71
152d6231b53b
hex19e74a7ed7

111254601431 has 2 divisors, whose sum is σ = 111254601432. Its totient is φ = 111254601430.

The previous prime is 111254601401. The next prime is 111254601433. The reversal of 111254601431 is 134106452111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111254601431 - 210 = 111254600407 is a prime.

It is a super-2 number, since 2×1112546014312 (a number of 23 digits) contains 22 as substring.

Together with 111254601433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 111254601394 and 111254601403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111254601433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55627300715 + 55627300716.

It is an arithmetic number, because the mean of its divisors is an integer number (55627300716).

Almost surely, 2111254601431 is an apocalyptic number.

111254601431 is a deficient number, since it is larger than the sum of its proper divisors (1).

111254601431 is an equidigital number, since it uses as much as digits as its factorization.

111254601431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 29.

The spelling of 111254601431 in words is "one hundred eleven billion, two hundred fifty-four million, six hundred one thousand, four hundred thirty-one".