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11125500503981 is a prime number
BaseRepresentation
bin1010000111100101101110…
…0000010110011110101101
31110101120212020222211202112
42201321123200112132231
52424240011112111411
635354552342533405
72225535162646433
oct241713340263655
943346766884675
1011125500503981
1135aa330aa2096
1212b8243737265
1362919006a5b6
142a6697226d53
151445ee4cdb8b
hexa1e5b8167ad

11125500503981 has 2 divisors, whose sum is σ = 11125500503982. Its totient is φ = 11125500503980.

The previous prime is 11125500503951. The next prime is 11125500504031. The reversal of 11125500503981 is 18930500552111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8933768301481 + 2191732202500 = 2988941^2 + 1480450^2 .

It is a cyclic number.

It is not a de Polignac number, because 11125500503981 - 26 = 11125500503917 is a prime.

It is a super-2 number, since 2×111255005039812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11125500503951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562750251990 + 5562750251991.

It is an arithmetic number, because the mean of its divisors is an integer number (5562750251991).

Almost surely, 211125500503981 is an apocalyptic number.

It is an amenable number.

11125500503981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11125500503981 is an equidigital number, since it uses as much as digits as its factorization.

11125500503981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 41.

The spelling of 11125500503981 in words is "eleven trillion, one hundred twenty-five billion, five hundred million, five hundred three thousand, nine hundred eighty-one".