1113001010083 has 2 divisors, whose sum is σ = 1113001010084. Its totient is φ = 1113001010082.

The previous prime is 1113001010039. The next prime is 1113001010111. The reversal of 1113001010083 is 3800101003111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1113001010083 - 2³⁷ = 975562056611 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1113001010083.

It is not a weakly prime, because it can be changed into another prime (1113001013083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556500505041 + 556500505042.

It is an arithmetic number, because the mean of its divisors is an integer number (556500505042).

Almost surely, 2^{1113001010083} is an apocalyptic number.

1113001010083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113001010083 is an equidigital number, since it uses as much as digits as its factorization.

1113001010083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1113001010083 its reverse (3800101003111), we get a palindrome (4913102013194).

The spelling of 1113001010083 in words is "one trillion, one hundred thirteen billion, one million, ten thousand, eighty-three".