1113001010111 has 2 divisors, whose sum is σ = 1113001010112. Its totient is φ = 1113001010110.

The previous prime is 1113001010083. The next prime is 1113001010161. The reversal of 1113001010111 is 1110101003111.

It is a weak prime.

It is an emirp because it is prime and its reverse (1110101003111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113001010111 - 2¹⁸ = 1113000747967 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113001010092 and 1113001010101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113001010161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556500505055 + 556500505056.

It is an arithmetic number, because the mean of its divisors is an integer number (556500505056).

Almost surely, 2^{1113001010111} is an apocalyptic number.

1113001010111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113001010111 is an equidigital number, since it uses as much as digits as its factorization.

1113001010111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 1113001010111 its reverse (1110101003111), we get a palindrome (2223102013222).

The spelling of 1113001010111 in words is "one trillion, one hundred thirteen billion, one million, ten thousand, one hundred eleven".