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111300112022 = 2115059096001
BaseRepresentation
bin110011110101000000…
…0001110111010010110
3101122021200210111210012
41213222000032322112
53310420312041042
6123044111400222
711020056225341
oct1475200167226
9348250714705
10111300112022
1143225014560
12196a2223072
13a659973b68
14555bb33458
152d6630ae82
hex19ea00ee96

111300112022 has 8 divisors (see below), whose sum is σ = 182127456072. Its totient is φ = 50590960000.

The previous prime is 111300112009. The next prime is 111300112051. The reversal of 111300112022 is 220211003111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1113001120222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111300111988 and 111300112006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2529547979 + ... + 2529548022.

It is an arithmetic number, because the mean of its divisors is an integer number (22765932009).

Almost surely, 2111300112022 is an apocalyptic number.

111300112022 is a deficient number, since it is larger than the sum of its proper divisors (70827344050).

111300112022 is a wasteful number, since it uses less digits than its factorization.

111300112022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5059096014.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 111300112022 its reverse (220211003111), we get a palindrome (331511115133).

It can be divided in two parts, 111300 and 112022, that added together give a palindrome (223322).

The spelling of 111300112022 in words is "one hundred eleven billion, three hundred million, one hundred twelve thousand, twenty-two".

Divisors: 1 2 11 22 5059096001 10118192002 55650056011 111300112022