Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01000001010001101 |
3 | 1001201200002012120211 |
4 | 22113121220022031 |
5 | 140243240343201 |
6 | 5040230442421 |
7 | 542545354312 |
oct | 122731501215 |
9 | 31650065524 |
10 | 11130012301 |
11 | 47a1668a81 |
12 | 21a7503411 |
13 | 1084b488c5 |
14 | 778274d09 |
15 | 4521c1651 |
hex | 29766828d |
11130012301 has 2 divisors, whose sum is σ = 11130012302. Its totient is φ = 11130012300.
The previous prime is 11130012277. The next prime is 11130012323. The reversal of 11130012301 is 10321003111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11091249225 + 38763076 = 105315^2 + 6226^2 .
It is a cyclic number.
It is not a de Polignac number, because 11130012301 - 215 = 11129979533 is a prime.
It is a super-2 number, since 2×111300123012 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11130012001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565006150 + 5565006151.
It is an arithmetic number, because the mean of its divisors is an integer number (5565006151).
Almost surely, 211130012301 is an apocalyptic number.
It is an amenable number.
11130012301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11130012301 is an equidigital number, since it uses as much as digits as its factorization.
11130012301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11130012301 its reverse (10321003111), we get a palindrome (21451015412).
The spelling of 11130012301 in words is "eleven billion, one hundred thirty million, twelve thousand, three hundred one".
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