Base | Representation |
---|---|
bin | 110011110101000000… |
… | …0100111000101001111 |
3 | 101122021200222112120220 |
4 | 1213222000213011033 |
5 | 3310420323223043 |
6 | 123044113442423 |
7 | 11020060120101 |
oct | 1475200470517 |
9 | 348250875526 |
10 | 111300211023 |
11 | 43225081981 |
12 | 196a2270413 |
13 | a6599a9c41 |
14 | 555bb5b571 |
15 | 2d6632a483 |
hex | 19ea02714f |
111300211023 has 4 divisors (see below), whose sum is σ = 148400281368. Its totient is φ = 74200140680.
The previous prime is 111300211021. The next prime is 111300211031. The reversal of 111300211023 is 320112003111.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320112003111 = 3 ⋅106704001037.
It is a cyclic number.
It is not a de Polignac number, because 111300211023 - 21 = 111300211021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111300210993 and 111300211011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111300211021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18550035168 + ... + 18550035173.
It is an arithmetic number, because the mean of its divisors is an integer number (37100070342).
Almost surely, 2111300211023 is an apocalyptic number.
111300211023 is a deficient number, since it is larger than the sum of its proper divisors (37100070345).
111300211023 is an equidigital number, since it uses as much as digits as its factorization.
111300211023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37100070344.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 111300211023 its reverse (320112003111), we get a palindrome (431412214134).
The spelling of 111300211023 in words is "one hundred eleven billion, three hundred million, two hundred eleven thousand, twenty-three".
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