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111300230122 = 255650115061
BaseRepresentation
bin110011110101000000…
…0101011101111101010
3101122021201000111210021
41213222000223233222
53310420324330442
6123044114111054
711020060226554
oct1475200535752
9348251014707
10111300230122
1143225095264
12196a227b48a
13a6599b5843
14555bb644d4
152d66330e67
hex19ea02bbea

111300230122 has 4 divisors (see below), whose sum is σ = 166950345186. Its totient is φ = 55650115060.

The previous prime is 111300230117. The next prime is 111300230123. The reversal of 111300230122 is 221032003111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 98068559281 + 13231670841 = 313159^2 + 115029^2 .

It is a super-2 number, since 2×1113002301222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111300230096 and 111300230105.

It is not an unprimeable number, because it can be changed into a prime (111300230123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27825057529 + ... + 27825057532.

Almost surely, 2111300230122 is an apocalyptic number.

111300230122 is a deficient number, since it is larger than the sum of its proper divisors (55650115064).

111300230122 is an equidigital number, since it uses as much as digits as its factorization.

111300230122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55650115063.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 111300230122 its reverse (221032003111), we get a palindrome (332332233233).

The spelling of 111300230122 in words is "one hundred eleven billion, three hundred million, two hundred thirty thousand, one hundred twenty-two".

Divisors: 1 2 55650115061 111300230122