11130031431230 has 16 divisors (see below), whose sum is σ = 20178186482160. Its totient is φ = 4419983704512.

The previous prime is 11130031431203. The next prime is 11130031431271. The reversal of 11130031431230 is 3213413003111.

It is a junction number, because it is equal to n+sod(n) for n = 11130031431196 and 11130031431205.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4003607039 + ... + 4003609818.

It is an arithmetic number, because the mean of its divisors is an integer number (1261136655135).

Almost surely, 2^{11130031431230} is an apocalyptic number.

11130031431230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11130031431230 is a deficient number, since it is larger than the sum of its proper divisors (9048155050930).

11130031431230 is a wasteful number, since it uses less digits than its factorization.

11130031431230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8007217003.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11130031431230 its reverse (3213413003111), we get a palindrome (14343444434341).

The spelling of 11130031431230 in words is "eleven trillion, one hundred thirty billion, thirty-one million, four hundred thirty-one thousand, two hundred thirty".