11130041119 has 2 divisors, whose sum is σ = 11130041120. Its totient is φ = 11130041118.

The previous prime is 11130041101. The next prime is 11130041137. The reversal of 11130041119 is 91114003111.

It is a balanced prime because it is at equal distance from previous prime (11130041101) and next prime (11130041137).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11130041119 is a prime.

It is a super-2 number, since 2×11130041119² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11130041119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11130044119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565020559 + 5565020560.

It is an arithmetic number, because the mean of its divisors is an integer number (5565020560).

Almost surely, 2^11130041119 is an apocalyptic number.

11130041119 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130041119 is an equidigital number, since it uses as much as digits as its factorization.

11130041119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 22.

The spelling of 11130041119 in words is "eleven billion, one hundred thirty million, forty-one thousand, one hundred nineteen".