11130042113 has 4 divisors (see below), whose sum is σ = 11430854100. Its totient is φ = 10829230128.

The previous prime is 11130042109. The next prime is 11130042173. The reversal of 11130042113 is 31124003111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9916773889 + 1213268224 = 99583^2 + 34832^2 .

It is a cyclic number.

It is not a de Polignac number, because 11130042113 - 2² = 11130042109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11130042091 and 11130042100.

It is not an unprimeable number, because it can be changed into a prime (11130042173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150405938 + ... + 150406011.

It is an arithmetic number, because the mean of its divisors is an integer number (2857713525).

Almost surely, 2^11130042113 is an apocalyptic number.

It is an amenable number.

11130042113 is a deficient number, since it is larger than the sum of its proper divisors (300811987).

11130042113 is an equidigital number, since it uses as much as digits as its factorization.

11130042113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300811986.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11130042113 its reverse (31124003111), we get a palindrome (42254045224).

The spelling of 11130042113 in words is "eleven billion, one hundred thirty million, forty-two thousand, one hundred thirteen".