Base | Representation |
---|---|
bin | 10000001100100100100… |
… | …010100000111110010011 |
3 | 10221101212112211202110211 |
4 | 100030210202200332103 |
5 | 121213420421314040 |
6 | 2211150505304551 |
7 | 143261262066211 |
oct | 20144442407623 |
9 | 3841775752424 |
10 | 1113009557395 |
11 | 39a02a97401a |
12 | 15b860795157 |
13 | 80c58145228 |
14 | 3bc271ddcb1 |
15 | 1de42b8e8ea |
hex | 103248a0f93 |
1113009557395 has 8 divisors (see below), whose sum is σ = 1414176849504. Its totient is φ = 838030725504.
The previous prime is 1113009557381. The next prime is 1113009557483. The reversal of 1113009557395 is 5937559003111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1113009557395 - 213 = 1113009549203 is a prime.
It is a super-2 number, since 2×11130095573952 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6547114959 + ... + 6547115128.
It is an arithmetic number, because the mean of its divisors is an integer number (176772106188).
Almost surely, 21113009557395 is an apocalyptic number.
1113009557395 is a deficient number, since it is larger than the sum of its proper divisors (301167292109).
1113009557395 is a wasteful number, since it uses less digits than its factorization.
1113009557395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13094230109.
The product of its (nonzero) digits is 637875, while the sum is 49.
The spelling of 1113009557395 in words is "one trillion, one hundred thirteen billion, nine million, five hundred fifty-seven thousand, three hundred ninety-five".
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