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11130215207 is a prime number
BaseRepresentation
bin10100101110110100…
…11001101100100111
31001201200110111220212
422113122121230213
5140243313341312
65040235050035
7542550161006
oct122732315447
931650414825
1011130215207
1147a1797471
1221a75a091b
131084bba077
147782c8c3d
15452211822
hex297699b27

11130215207 has 2 divisors, whose sum is σ = 11130215208. Its totient is φ = 11130215206.

The previous prime is 11130215203. The next prime is 11130215263. The reversal of 11130215207 is 70251203111.

It is a weak prime.

It is an emirp because it is prime and its reverse (70251203111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11130215207 - 22 = 11130215203 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11130215203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565107603 + 5565107604.

It is an arithmetic number, because the mean of its divisors is an integer number (5565107604).

Almost surely, 211130215207 is an apocalyptic number.

11130215207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130215207 is an equidigital number, since it uses as much as digits as its factorization.

11130215207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 11130215207 its reverse (70251203111), we get a palindrome (81381418318).

The spelling of 11130215207 in words is "eleven billion, one hundred thirty million, two hundred fifteen thousand, two hundred seven".