Base | Representation |
---|---|
bin | 110011110101000101… |
… | …1101101010010001101 |
3 | 101122021220110022222021 |
4 | 1213222023231102031 |
5 | 3310422044320023 |
6 | 123044300050141 |
7 | 11020123624111 |
oct | 1475213552215 |
9 | 348256408867 |
10 | 111303120013 |
11 | 432267894a8 |
12 | 196a3233951 |
13 | a65a488037 |
14 | 555c2b7741 |
15 | 2d6670235d |
hex | 19ea2ed48d |
111303120013 has 2 divisors, whose sum is σ = 111303120014. Its totient is φ = 111303120012.
The previous prime is 111303119959. The next prime is 111303120043. The reversal of 111303120013 is 310021303111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103116127689 + 8186992324 = 321117^2 + 90482^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111303120013 is a prime.
It is a super-2 number, since 2×1113031200132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111303120043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55651560006 + 55651560007.
It is an arithmetic number, because the mean of its divisors is an integer number (55651560007).
Almost surely, 2111303120013 is an apocalyptic number.
It is an amenable number.
111303120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
111303120013 is an equidigital number, since it uses as much as digits as its factorization.
111303120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 111303120013 its reverse (310021303111), we get a palindrome (421324423124).
The spelling of 111303120013 in words is "one hundred eleven billion, three hundred three million, one hundred twenty thousand, thirteen".
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