11130969131 has 2 divisors, whose sum is σ = 11130969132. Its totient is φ = 11130969130.

The previous prime is 11130969103. The next prime is 11130969133. The reversal of 11130969131 is 13196903111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11130969131 - 2¹⁴ = 11130952747 is a prime.

It is a super-2 number, since 2×11130969131² (a number of 21 digits) contains 22 as substring.

Together with 11130969133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11130969091 and 11130969100.

It is not a weakly prime, because it can be changed into another prime (11130969133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565484565 + 5565484566.

It is an arithmetic number, because the mean of its divisors is an integer number (5565484566).

Almost surely, 2^11130969131 is an apocalyptic number.

11130969131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130969131 is an equidigital number, since it uses as much as digits as its factorization.

11130969131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 35.

It can be divided in two parts, 11 and 130969131, that multiplied together give a palindrome (1440660441).

The spelling of 11130969131 in words is "eleven billion, one hundred thirty million, nine hundred sixty-nine thousand, one hundred thirty-one".