1113110120141 has 2 divisors, whose sum is σ = 1113110120142. Its totient is φ = 1113110120140.

The previous prime is 1113110120047. The next prime is 1113110120183. The reversal of 1113110120141 is 1410210113111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 659743564516 + 453366555625 = 812246^2 + 673325^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113110120141 is a prime.

It is a super-2 number, since 2×1113110120141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113110120191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556555060070 + 556555060071.

It is an arithmetic number, because the mean of its divisors is an integer number (556555060071).

Almost surely, 2^{1113110120141} is an apocalyptic number.

It is an amenable number.

1113110120141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113110120141 is an equidigital number, since it uses as much as digits as its factorization.

1113110120141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 1113110120141 its reverse (1410210113111), we get a palindrome (2523320233252).

The spelling of 1113110120141 in words is "one trillion, one hundred thirteen billion, one hundred ten million, one hundred twenty thousand, one hundred forty-one".