111311414101 has 4 divisors (see below), whose sum is σ = 117169909600. Its totient is φ = 105452918604.

The previous prime is 111311414069. The next prime is 111311414107. The reversal of 111311414101 is 101414113111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 101414113111 = 541 ⋅187456771.

It is a cyclic number.

It is not a de Polignac number, because 111311414101 - 2⁵ = 111311414069 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 5858495479 = 111311414101 / (1 + 1 + 1 + 3 + 1 + 1 + 4 + 1 + 4 + 1 + 0 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111311414107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2929247721 + ... + 2929247758.

It is an arithmetic number, because the mean of its divisors is an integer number (29292477400).

Almost surely, 2^111311414101 is an apocalyptic number.

It is an amenable number.

111311414101 is a deficient number, since it is larger than the sum of its proper divisors (5858495499).

111311414101 is an equidigital number, since it uses as much as digits as its factorization.

111311414101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5858495498.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 111311414101 its reverse (101414113111), we get a palindrome (212725527212).

The spelling of 111311414101 in words is "one hundred eleven billion, three hundred eleven million, four hundred fourteen thousand, one hundred one".