Base | Representation |
---|---|
bin | 100001001011000… |
… | …1111001001000011 |
3 | 2212120112122001021 |
4 | 1002112033021003 |
5 | 4234430003233 |
6 | 302242050311 |
7 | 36404260453 |
oct | 10226171103 |
9 | 2776478037 |
10 | 1113125443 |
11 | 52136a691 |
12 | 270949997 |
13 | 1497c8011 |
14 | a7b97d63 |
15 | 67ac9e2d |
hex | 4258f243 |
1113125443 has 2 divisors, whose sum is σ = 1113125444. Its totient is φ = 1113125442.
The previous prime is 1113125437. The next prime is 1113125449. The reversal of 1113125443 is 3445213111.
It is a balanced prime because it is at equal distance from previous prime (1113125437) and next prime (1113125449).
It is an emirp because it is prime and its reverse (3445213111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113125443 - 213 = 1113117251 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113125449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556562721 + 556562722.
It is an arithmetic number, because the mean of its divisors is an integer number (556562722).
Almost surely, 21113125443 is an apocalyptic number.
1113125443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113125443 is an equidigital number, since it uses as much as digits as its factorization.
1113125443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 1113125443 is about 33363.5346298920. The cubic root of 1113125443 is about 1036.3696905531.
Adding to 1113125443 its reverse (3445213111), we get a palindrome (4558338554).
The spelling of 1113125443 in words is "one billion, one hundred thirteen million, one hundred twenty-five thousand, four hundred forty-three".
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