111313000230023 has 4 divisors (see below), whose sum is σ = 111313037806320. Its totient is φ = 111312962653728.

The previous prime is 111313000230001. The next prime is 111313000230037. The reversal of 111313000230023 is 320032000313111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111313000230023 - 2¹² = 111313000225927 is a prime.

It is a super-4 number, since 4×111313000230023⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111313000229977 and 111313000230004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111313000230053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13925090 + ... + 20409167.

It is an arithmetic number, because the mean of its divisors is an integer number (27828259451580).

Almost surely, 2^{111313000230023} is an apocalyptic number.

111313000230023 is a deficient number, since it is larger than the sum of its proper divisors (37576297).

111313000230023 is an equidigital number, since it uses as much as digits as its factorization.

111313000230023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37576296.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 111313000230023 its reverse (320032000313111), we get a palindrome (431345000543134).

The spelling of 111313000230023 in words is "one hundred eleven trillion, three hundred thirteen billion, two hundred thirty thousand, twenty-three".