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111313032321013 is a prime number
BaseRepresentation
bin11001010011110100010101…
…110000000001011111110101
3112121010102101121111201220021
4121103310111300001133311
5104042223042233233023
61032424300123205141
732306046465222235
oct3123642560013765
9477112347451807
10111313032321013
1132516656903016
12105992653767b1
134a15a0a375b43
141d6b818269cc5
15cd079282135d
hex653d15c017f5

111313032321013 has 2 divisors, whose sum is σ = 111313032321014. Its totient is φ = 111313032321012.

The previous prime is 111313032321011. The next prime is 111313032321053. The reversal of 111313032321013 is 310123230313111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102453730095249 + 8859302225764 = 10121943^2 + 2976458^2 .

It is a cyclic number.

It is not a de Polignac number, because 111313032321013 - 21 = 111313032321011 is a prime.

Together with 111313032321011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111313032321011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656516160506 + 55656516160507.

It is an arithmetic number, because the mean of its divisors is an integer number (55656516160507).

Almost surely, 2111313032321013 is an apocalyptic number.

It is an amenable number.

111313032321013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111313032321013 is an equidigital number, since it uses as much as digits as its factorization.

111313032321013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 111313032321013 its reverse (310123230313111), we get a palindrome (421436262634124).

The spelling of 111313032321013 in words is "one hundred eleven trillion, three hundred thirteen billion, thirty-two million, three hundred twenty-one thousand, thirteen".