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1113191520053 is a prime number
BaseRepresentation
bin10000001100101111011…
…000101001011100110101
310221102100020020102022112
4100030233120221130311
5121214304012120203
62211220525340405
7143265631540454
oct20145730513465
93842306212275
101113191520053
1139a113657288
1215b8b1707705
1380c86a55542
143bc43448b9b
151de53b346d8
hex1032f629735

1113191520053 has 2 divisors, whose sum is σ = 1113191520054. Its totient is φ = 1113191520052.

The previous prime is 1113191520047. The next prime is 1113191520059. The reversal of 1113191520053 is 3500251913111.

It is a balanced prime because it is at equal distance from previous prime (1113191520047) and next prime (1113191520059).

It can be written as a sum of positive squares in only one way, i.e., 781700003044 + 331491517009 = 884138^2 + 575753^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113191520053 - 24 = 1113191520037 is a prime.

It is a super-2 number, since 2×11131915200532 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113191520059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556595760026 + 556595760027.

It is an arithmetic number, because the mean of its divisors is an integer number (556595760027).

Almost surely, 21113191520053 is an apocalyptic number.

It is an amenable number.

1113191520053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113191520053 is an equidigital number, since it uses as much as digits as its factorization.

1113191520053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050, while the sum is 32.

The spelling of 1113191520053 in words is "one trillion, one hundred thirteen billion, one hundred ninety-one million, five hundred twenty thousand, fifty-three".