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11131925294093 is a prime number
BaseRepresentation
bin1010000111111101101001…
…1100111110110000001101
31110102012110000100222220212
42201333122130332300031
52424341140333402333
635401534052252205
72226153325526102
oct241773234766015
943365400328825
1011131925294093
11360202868aa8a
1212b9537311065
13629975147456
142a6b06610aa9
15144878575448
hexa1fda73ec0d

11131925294093 has 2 divisors, whose sum is σ = 11131925294094. Its totient is φ = 11131925294092.

The previous prime is 11131925294089. The next prime is 11131925294197. The reversal of 11131925294093 is 39049252913111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9880598928964 + 1251326365129 = 3143342^2 + 1118627^2 .

It is a cyclic number.

It is not a de Polignac number, because 11131925294093 - 22 = 11131925294089 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11131925290093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565962647046 + 5565962647047.

It is an arithmetic number, because the mean of its divisors is an integer number (5565962647047).

Almost surely, 211131925294093 is an apocalyptic number.

It is an amenable number.

11131925294093 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131925294093 is an equidigital number, since it uses as much as digits as its factorization.

11131925294093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 524880, while the sum is 50.

The spelling of 11131925294093 in words is "eleven trillion, one hundred thirty-one billion, nine hundred twenty-five million, two hundred ninety-four thousand, ninety-three".