11131925294197 has 2 divisors, whose sum is σ = 11131925294198. Its totient is φ = 11131925294196.

The previous prime is 11131925294093. The next prime is 11131925294209. The reversal of 11131925294197 is 79149252913111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11131925294116 + 81 = 3336454^2 + 9^2 .

It is a cyclic number.

It is not a de Polignac number, because 11131925294197 - 2³¹ = 11129777810549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11131925294797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565962647098 + 5565962647099.

It is an arithmetic number, because the mean of its divisors is an integer number (5565962647099).

Almost surely, 2^{11131925294197} is an apocalyptic number.

It is an amenable number.

11131925294197 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131925294197 is an equidigital number, since it uses as much as digits as its factorization.

11131925294197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1224720, while the sum is 55.

The spelling of 11131925294197 in words is "eleven trillion, one hundred thirty-one billion, nine hundred twenty-five million, two hundred ninety-four thousand, one hundred ninety-seven".