Base | Representation |
---|---|
bin | 10000001100110001001… |
… | …010010101101000100111 |
3 | 10221102102022022120200121 |
4 | 100030301022111220213 |
5 | 121214334124321203 |
6 | 2211223512222411 |
7 | 143266443056425 |
oct | 20146112255047 |
9 | 3842368276617 |
10 | 1113221323303 |
11 | 39a129462971 |
12 | 15b8bb69aa07 |
13 | 80c8cc8babb |
14 | 3bc473a6115 |
15 | 1de565700bd |
hex | 10331295a27 |
1113221323303 has 2 divisors, whose sum is σ = 1113221323304. Its totient is φ = 1113221323302.
The previous prime is 1113221323273. The next prime is 1113221323321. The reversal of 1113221323303 is 3033231223111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113221323303 - 25 = 1113221323271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113221323343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556610661651 + 556610661652.
It is an arithmetic number, because the mean of its divisors is an integer number (556610661652).
Almost surely, 21113221323303 is an apocalyptic number.
1113221323303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113221323303 is an equidigital number, since it uses as much as digits as its factorization.
1113221323303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1113221323303 its reverse (3033231223111), we get a palindrome (4146452546414).
The spelling of 1113221323303 in words is "one trillion, one hundred thirteen billion, two hundred twenty-one million, three hundred twenty-three thousand, three hundred three".
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