Base | Representation |
---|---|
bin | 10000001100110001101… |
… | …111101001000010101111 |
3 | 10221102102222201101201021 |
4 | 100030301233221002233 |
5 | 121214344130232002 |
6 | 2211224501555011 |
7 | 143266622145214 |
oct | 20146157510257 |
9 | 3842388641637 |
10 | 1113231102127 |
11 | 39a133a31941 |
12 | 15b902a15a67 |
13 | 80c92003aa1 |
14 | 3bc487cdb0b |
15 | 1de57352737 |
hex | 10331be90af |
1113231102127 has 2 divisors, whose sum is σ = 1113231102128. Its totient is φ = 1113231102126.
The previous prime is 1113231102121. The next prime is 1113231102133. The reversal of 1113231102127 is 7212011323111.
It is a balanced prime because it is at equal distance from previous prime (1113231102121) and next prime (1113231102133).
It is a cyclic number.
It is not a de Polignac number, because 1113231102127 - 239 = 563475288239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113231102121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556615551063 + 556615551064.
It is an arithmetic number, because the mean of its divisors is an integer number (556615551064).
Almost surely, 21113231102127 is an apocalyptic number.
1113231102127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113231102127 is an equidigital number, since it uses as much as digits as its factorization.
1113231102127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1113231102127 its reverse (7212011323111), we get a palindrome (8325242425238).
The spelling of 1113231102127 in words is "one trillion, one hundred thirteen billion, two hundred thirty-one million, one hundred two thousand, one hundred twenty-seven".
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