Base | Representation |
---|---|
bin | 1010000111111111001011… |
… | …0000010011001000100101 |
3 | 1110102020111102120012001022 |
4 | 2201333302300103020211 |
5 | 2424343004222331433 |
6 | 35402042335140525 |
7 | 2226166406212421 |
oct | 241776260231045 |
9 | 43366442505038 |
10 | 11132333011493 |
11 | 3602217847111 |
12 | 12b962b974745 |
13 | 629a0b75b655 |
14 | 2a6b44823b81 |
15 | 14489e260698 |
hex | a1ff2c13225 |
11132333011493 has 2 divisors, whose sum is σ = 11132333011494. Its totient is φ = 11132333011492.
The previous prime is 11132333011433. The next prime is 11132333011589. The reversal of 11132333011493 is 39411033323111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6968929456129 + 4163403555364 = 2639873^2 + 2040442^2 .
It is a cyclic number.
It is not a de Polignac number, because 11132333011493 - 28 = 11132333011237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11132333011433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566166505746 + 5566166505747.
It is an arithmetic number, because the mean of its divisors is an integer number (5566166505747).
Almost surely, 211132333011493 is an apocalyptic number.
It is an amenable number.
11132333011493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132333011493 is an equidigital number, since it uses as much as digits as its factorization.
11132333011493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 35.
The spelling of 11132333011493 in words is "eleven trillion, one hundred thirty-two billion, three hundred thirty-three million, eleven thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •