11132333011433 has 2 divisors, whose sum is σ = 11132333011434. Its totient is φ = 11132333011432.

The previous prime is 11132333011409. The next prime is 11132333011493. The reversal of 11132333011433 is 33411033323111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11005195838464 + 127137172969 = 3317408^2 + 356563^2 .

It is a cyclic number.

It is not a de Polignac number, because 11132333011433 - 2¹⁶ = 11132332945897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11132333011396 and 11132333011405.

It is not a weakly prime, because it can be changed into another prime (11132333011493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566166505716 + 5566166505717.

It is an arithmetic number, because the mean of its divisors is an integer number (5566166505717).

Almost surely, 2^{11132333011433} is an apocalyptic number.

It is an amenable number.

11132333011433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132333011433 is an equidigital number, since it uses as much as digits as its factorization.

11132333011433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 11132333011433 its reverse (33411033323111), we get a palindrome (44543366334544).

The spelling of 11132333011433 in words is "eleven trillion, one hundred thirty-two billion, three hundred thirty-three million, eleven thousand, four hundred thirty-three".