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11133010311012 = 2232309250286417
BaseRepresentation
bin1010001000000001101100…
…0111111111011101100100
31110102022020122000120022200
42202000123013333131210
52424400401114423022
635402233452054500
72226222242156532
oct242003307773544
943368218016280
1011133010311012
1136025350a1287
1212b979a764430
13629ab8b803b5
142a6baa76d152
151448dd94bbac
hexa201b1ff764

11133010311012 has 18 divisors (see below), whose sum is σ = 28141776064038. Its totient is φ = 3711003436992.

The previous prime is 11133010310969. The next prime is 11133010311019. The reversal of 11133010311012 is 21011301033111.

11133010311012 is a `hidden beast` number, since 1 + 1 + 1 + 330 + 10 + 311 + 0 + 12 = 666.

11133010311012 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 7056067818276 + 4076942492736 = 2656326^2 + 2019144^2 .

It is a tau number, because it is divible by the number of its divisors (18).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (11133010311019) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 154625143173 + ... + 154625143244.

Almost surely, 211133010311012 is an apocalyptic number.

11133010311012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11133010311012 is an abundant number, since it is smaller than the sum of its proper divisors (17008765753026).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11133010311012 is a wasteful number, since it uses less digits than its factorization.

11133010311012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 309250286427 (or 309250286422 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11133010311012 its reverse (21011301033111), we get a palindrome (32144311344123).

The spelling of 11133010311012 in words is "eleven trillion, one hundred thirty-three billion, ten million, three hundred eleven thousand, twelve".

Divisors: 1 2 3 4 6 9 12 18 36 309250286417 618500572834 927750859251 1237001145668 1855501718502 2783252577753 3711003437004 5566505155506 11133010311012