11133030000013 has 4 divisors (see below), whose sum is σ = 11159600477760. Its totient is φ = 11106459522268.

The previous prime is 11133029999989. The next prime is 11133030000073. The reversal of 11133030000013 is 31000003033111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133030000013 - 2²¹ = 11133027902861 is a prime.

It is a super-3 number, since 3×11133030000013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11133030000073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13285238245 + ... + 13285239082.

It is an arithmetic number, because the mean of its divisors is an integer number (2789900119440).

Almost surely, 2^{11133030000013} is an apocalyptic number.

It is an amenable number.

11133030000013 is a deficient number, since it is larger than the sum of its proper divisors (26570477747).

11133030000013 is an equidigital number, since it uses as much as digits as its factorization.

11133030000013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26570477746.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11133030000013 its reverse (31000003033111), we get a palindrome (42133033033124).

The spelling of 11133030000013 in words is "eleven trillion, one hundred thirty-three billion, thirty million, thirteen", and thus it is an aban number.