Base | Representation |
---|---|
bin | 10100101111001010… |
… | …01001111010001111 |
3 | 1001201212202201202022 |
4 | 22113211021322033 |
5 | 140300024043002 |
6 | 5040415320355 |
7 | 542613141305 |
oct | 122745117217 |
9 | 31655681668 |
10 | 11133034127 |
11 | 47a3342356 |
12 | 21a85200bb |
13 | 1085666177 |
14 | 778820275 |
15 | 4525bbba2 |
hex | 297949e8f |
11133034127 has 2 divisors, whose sum is σ = 11133034128. Its totient is φ = 11133034126.
The previous prime is 11133034111. The next prime is 11133034147. The reversal of 11133034127 is 72143033111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11133034127 - 24 = 11133034111 is a prime.
It is a super-3 number, since 3×111330341273 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11133034096 and 11133034105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133034147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566517063 + 5566517064.
It is an arithmetic number, because the mean of its divisors is an integer number (5566517064).
Almost surely, 211133034127 is an apocalyptic number.
11133034127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133034127 is an equidigital number, since it uses as much as digits as its factorization.
11133034127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 11133034127 its reverse (72143033111), we get a palindrome (83276067238).
The spelling of 11133034127 in words is "eleven billion, one hundred thirty-three million, thirty-four thousand, one hundred twenty-seven".
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