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1113308106853 is a prime number
BaseRepresentation
bin10000001100110110010…
…101011001000001100101
310221102122100121122100011
4100030312111121001211
5121220023333404403
62211240252250221
7143301545524615
oct20146625310145
93842570548304
101113308106853
1139a173447708
1215b924770971
1380ca4c55a07
143bc54b16a45
151de5deb3a6d
hex10336559065

1113308106853 has 2 divisors, whose sum is σ = 1113308106854. Its totient is φ = 1113308106852.

The previous prime is 1113308106829. The next prime is 1113308106913. The reversal of 1113308106853 is 3586018033111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 922249074244 + 191059032609 = 960338^2 + 437103^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1113308106853 is a prime.

It is a super-2 number, since 2×11133081068532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113308106653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556654053426 + 556654053427.

It is an arithmetic number, because the mean of its divisors is an integer number (556654053427).

Almost surely, 21113308106853 is an apocalyptic number.

It is an amenable number.

1113308106853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113308106853 is an equidigital number, since it uses as much as digits as its factorization.

1113308106853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 40.

The spelling of 1113308106853 in words is "one trillion, one hundred thirteen billion, three hundred eight million, one hundred six thousand, eight hundred fifty-three".