11133110020013 has 2 divisors, whose sum is σ = 11133110020014. Its totient is φ = 11133110020012.

The previous prime is 11133110019973. The next prime is 11133110020057. The reversal of 11133110020013 is 31002001133111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10620279301129 + 512830718884 = 3258877^2 + 716122^2 .

It is a cyclic number.

It is not a de Polignac number, because 11133110020013 - 2⁴² = 6735063508909 is a prime.

It is a super-2 number, since 2×11133110020013² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11133110019973 and 11133110020000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11133110020213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566555010006 + 5566555010007.

It is an arithmetic number, because the mean of its divisors is an integer number (5566555010007).

Almost surely, 2^{11133110020013} is an apocalyptic number.

It is an amenable number.

11133110020013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133110020013 is an equidigital number, since it uses as much as digits as its factorization.

11133110020013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11133110020013 its reverse (31002001133111), we get a palindrome (42135111153124).

The spelling of 11133110020013 in words is "eleven trillion, one hundred thirty-three billion, one hundred ten million, twenty thousand, thirteen".