Base | Representation |
---|---|
bin | 100001001011011… |
… | …1100101101110011 |
3 | 2212120220010010001 |
4 | 1002112330231303 |
5 | 4240001441430 |
6 | 302250050431 |
7 | 36405665626 |
oct | 10226745563 |
9 | 2776803101 |
10 | 1113312115 |
11 | 521487963 |
12 | 270a19a17 |
13 | 149861c86 |
14 | a7c05dbd |
15 | 67b153ca |
hex | 425bcb73 |
1113312115 has 4 divisors (see below), whose sum is σ = 1335974544. Its totient is φ = 890649688.
The previous prime is 1113312091. The next prime is 1113312119. The reversal of 1113312115 is 5112133111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1113312115 - 213 = 1113303923 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1113312092 and 1113312101.
It is not an unprimeable number, because it can be changed into a prime (1113312119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111331207 + ... + 111331216.
It is an arithmetic number, because the mean of its divisors is an integer number (333993636).
Almost surely, 21113312115 is an apocalyptic number.
1113312115 is a deficient number, since it is larger than the sum of its proper divisors (222662429).
1113312115 is an equidigital number, since it uses as much as digits as its factorization.
1113312115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222662428.
The product of its digits is 90, while the sum is 19.
The square root of 1113312115 is about 33366.3320579293. The cubic root of 1113312115 is about 1036.4276206485.
Adding to 1113312115 its reverse (5112133111), we get a palindrome (6225445226).
The spelling of 1113312115 in words is "one billion, one hundred thirteen million, three hundred twelve thousand, one hundred fifteen".
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