Base | Representation |
---|---|
bin | 10000001100110110100… |
… | …101000010110001000111 |
3 | 10221102122122100002210020 |
4 | 100030312211002301013 |
5 | 121220030411204431 |
6 | 2211240520230223 |
7 | 143301625434252 |
oct | 20146645026107 |
9 | 3842578302706 |
10 | 1113312209991 |
11 | 39a17579a433 |
12 | 15b92600b373 |
13 | 80ca5a614c7 |
14 | 3bc554a4099 |
15 | 1de5e524696 |
hex | 10336942c47 |
1113312209991 has 4 divisors (see below), whose sum is σ = 1484416279992. Its totient is φ = 742208139992.
The previous prime is 1113312209941. The next prime is 1113312210013. The reversal of 1113312209991 is 1999022133111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1113312209991 - 230 = 1112238468167 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113312209941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185552034996 + ... + 185552035001.
It is an arithmetic number, because the mean of its divisors is an integer number (371104069998).
Almost surely, 21113312209991 is an apocalyptic number.
1113312209991 is a deficient number, since it is larger than the sum of its proper divisors (371104070001).
1113312209991 is an equidigital number, since it uses as much as digits as its factorization.
1113312209991 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 371104070000.
The product of its (nonzero) digits is 26244, while the sum is 42.
The spelling of 1113312209991 in words is "one trillion, one hundred thirteen billion, three hundred twelve million, two hundred nine thousand, nine hundred ninety-one".
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