Base | Representation |
---|---|
bin | 10000001100110110100… |
… | …101000010110001100011 |
3 | 10221102122122100002211021 |
4 | 100030312211002301203 |
5 | 121220030411210034 |
6 | 2211240520230311 |
7 | 143301625434322 |
oct | 20146645026143 |
9 | 3842578302737 |
10 | 1113312210019 |
11 | 39a17579a459 |
12 | 15b92600b397 |
13 | 80ca5a61519 |
14 | 3bc554a40b9 |
15 | 1de5e5246b4 |
hex | 10336942c63 |
1113312210019 has 2 divisors, whose sum is σ = 1113312210020. Its totient is φ = 1113312210018.
The previous prime is 1113312210013. The next prime is 1113312210037. The reversal of 1113312210019 is 9100122133111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113312210019 - 227 = 1113177992291 is a prime.
It is a super-2 number, since 2×11133122100192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113312209975 and 1113312210002.
It is not a weakly prime, because it can be changed into another prime (1113312210013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656105009 + 556656105010.
It is an arithmetic number, because the mean of its divisors is an integer number (556656105010).
Almost surely, 21113312210019 is an apocalyptic number.
1113312210019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113312210019 is an equidigital number, since it uses as much as digits as its factorization.
1113312210019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 1113312210019 in words is "one trillion, one hundred thirteen billion, three hundred twelve million, two hundred ten thousand, nineteen".
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