1113312301397 has 2 divisors, whose sum is σ = 1113312301398. Its totient is φ = 1113312301396.

The previous prime is 1113312301391. The next prime is 1113312301399. The reversal of 1113312301397 is 7931032133111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1088587569316 + 24724732081 = 1043354^2 + 157241^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113312301397 - 2³⁸ = 838434394453 is a prime.

Together with 1113312301399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113312301391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656150698 + 556656150699.

It is an arithmetic number, because the mean of its divisors is an integer number (556656150699).

Almost surely, 2^{1113312301397} is an apocalyptic number.

It is an amenable number.

1113312301397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113312301397 is an equidigital number, since it uses as much as digits as its factorization.

1113312301397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10206, while the sum is 35.

The spelling of 1113312301397 in words is "one trillion, one hundred thirteen billion, three hundred twelve million, three hundred one thousand, three hundred ninety-seven".