Base | Representation |
---|---|
bin | 1010001000000011010001… |
… | …0110000100110000011000 |
3 | 1110102100100010012101201120 |
4 | 2202000310112010300120 |
5 | 2424402232424324422 |
6 | 35402343445045240 |
7 | 2226235600512624 |
oct | 242006426046030 |
9 | 43370303171646 |
10 | 11133433433112 |
11 | 3602731a1a171 |
12 | 12b98983b6820 |
13 | 629b557291c3 |
14 | 2a6c0aa32184 |
15 | 144915b7b45c |
hex | a2034584c18 |
11133433433112 has 128 divisors (see below), whose sum is σ = 28858515840000. Its totient is φ = 3576830100480.
The previous prime is 11133433433093. The next prime is 11133433433201. The reversal of 11133433433112 is 21133433433111.
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 140270014 + ... + 140349362.
It is an arithmetic number, because the mean of its divisors is an integer number (225457155000).
Almost surely, 211133433433112 is an apocalyptic number.
11133433433112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11133433433112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14429257920000).
11133433433112 is an abundant number, since it is smaller than the sum of its proper divisors (17725082406888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11133433433112 is a wasteful number, since it uses less digits than its factorization.
11133433433112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81201 (or 81197 counting only the distinct ones).
The product of its digits is 23328, while the sum is 33.
Adding to 11133433433112 its reverse (21133433433111), we get a palindrome (32266866866223).
Subtracting 11133433433112 from its reverse (21133433433111), we obtain a palindrome (9999999999999).
The spelling of 11133433433112 in words is "eleven trillion, one hundred thirty-three billion, four hundred thirty-three million, four hundred thirty-three thousand, one hundred twelve".
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