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11133433433112 = 2334379172179349
BaseRepresentation
bin1010001000000011010001…
…0110000100110000011000
31110102100100010012101201120
42202000310112010300120
52424402232424324422
635402343445045240
72226235600512624
oct242006426046030
943370303171646
1011133433433112
113602731a1a171
1212b98983b6820
13629b557291c3
142a6c0aa32184
15144915b7b45c
hexa2034584c18

11133433433112 has 128 divisors (see below), whose sum is σ = 28858515840000. Its totient is φ = 3576830100480.

The previous prime is 11133433433093. The next prime is 11133433433201. The reversal of 11133433433112 is 21133433433111.

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 140270014 + ... + 140349362.

It is an arithmetic number, because the mean of its divisors is an integer number (225457155000).

Almost surely, 211133433433112 is an apocalyptic number.

11133433433112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11133433433112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14429257920000).

11133433433112 is an abundant number, since it is smaller than the sum of its proper divisors (17725082406888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11133433433112 is a wasteful number, since it uses less digits than its factorization.

11133433433112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81201 (or 81197 counting only the distinct ones).

The product of its digits is 23328, while the sum is 33.

Adding to 11133433433112 its reverse (21133433433111), we get a palindrome (32266866866223).

Subtracting 11133433433112 from its reverse (21133433433111), we obtain a palindrome (9999999999999).

The spelling of 11133433433112 in words is "eleven trillion, one hundred thirty-three billion, four hundred thirty-three million, four hundred thirty-three thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 24 43 79 86 129 158 172 237 258 316 344 474 516 632 948 1032 1721 1896 3397 3442 5163 6794 6884 10191 10326 13588 13768 20382 20652 27176 40764 41304 74003 79349 81528 135959 148006 158698 222009 238047 271918 296012 317396 407877 444018 476094 543836 592024 634792 815754 888036 952188 1087672 1631508 1776072 1904376 3263016 3412007 5846237 6268571 6824014 10236021 11692474 12537142 13648028 17538711 18805713 20472042 23384948 25074284 27296056 35077422 37611426 40944084 46769896 50148568 70154844 75222852 81888168 136559629 140309688 150445704 269548553 273119258 409678887 539097106 546238516 808645659 819357774 1078194212 1092477032 1617291318 1638715548 2156388424 3234582636 3277431096 5872064047 6469165272 10788210691 11744128094 17616192141 21576421382 23488256188 32364632073 35232384282 43152842764 46976512376 64729264146 70464768564 86305685528 129458528292 140929537128 258917056584 463893059713 927786119426 1391679179139 1855572238852 2783358358278 3711144477704 5566716716556 11133433433112