111341130104341 has 2 divisors, whose sum is σ = 111341130104342. Its totient is φ = 111341130104340.

The previous prime is 111341130104221. The next prime is 111341130104371. The reversal of 111341130104341 is 143401031143111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110515894123716 + 825235980625 = 10512654^2 + 908425^2 .

It is a cyclic number.

It is not a de Polignac number, because 111341130104341 - 2¹³ = 111341130096149 is a prime.

It is a super-5 number, since 5×111341130104341⁵ (a number of 71 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111341130104371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55670565052170 + 55670565052171.

It is an arithmetic number, because the mean of its divisors is an integer number (55670565052171).

Almost surely, 2^{111341130104341} is an apocalyptic number.

It is an amenable number.

111341130104341 is a deficient number, since it is larger than the sum of its proper divisors (1).

111341130104341 is an equidigital number, since it uses as much as digits as its factorization.

111341130104341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 111341130104341 its reverse (143401031143111), we get a palindrome (254742161247452).

The spelling of 111341130104341 in words is "one hundred eleven trillion, three hundred forty-one billion, one hundred thirty million, one hundred four thousand, three hundred forty-one".