1113433134097 has 2 divisors, whose sum is σ = 1113433134098. Its totient is φ = 1113433134096.

The previous prime is 1113433134031. The next prime is 1113433134113. The reversal of 1113433134097 is 7904313343111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1081914102801 + 31519031296 = 1040151^2 + 177536^2 .

It is an emirp because it is prime and its reverse (7904313343111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113433134097 - 2²⁷ = 1113298916369 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113433174097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556716567048 + 556716567049.

It is an arithmetic number, because the mean of its divisors is an integer number (556716567049).

Almost surely, 2^{1113433134097} is an apocalyptic number.

It is an amenable number.

1113433134097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113433134097 is an equidigital number, since it uses as much as digits as its factorization.

1113433134097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 1113433134097 in words is "one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred thirty-four thousand, ninety-seven".